1 😎 Language Foundation Courses Learn any programming language from scratch and understand all its fundamentals concepts for a strong programming foundation in the easiest possible manner with help of GeeksforGeeks Language Foundation Courses – Java Foundation | Python Foundation | C++ Foundation2 😉 Geeks Classes Live Get interview-centric live online classes on Data Structure and Algorithms from any geographical location to learn and master DSA concepts for enhancing your problem-solving & programming skills and to crack the interview of any product-based company – Geeks Classes: Live Session3 😁 All-inclusive Interview Preparation. Get all of your interview preparation at one place. DSA Self Paced Learn data structures and algorithms to help you prepare for interview with IT leaders like Microsoft, Amazon, Adobe. DSA Self-Paced Course will allow you to master DSA at your own pace. Company Specific Courses – Amazon, Microsoft, TCS & Wipro Crack the interview of any product-based giant company by specifically preparing with the questions that these companies usually ask Interview round for coding. Refer GeeksforGeeks Company-Specific Courses: Amazon SDE Testing Series, etc. 
# Iterative Binary Search Function method Python Implementation # It returns index # Otherwise returns 1 def binary_search (list1,n): low = 0, high = len(1) – 1 mid=0, while low n : high = mid (1) # Initial list1 = 45 # Function call results = binary_search (1list1,n) print(Element present at index, str(result), else print(Element not found in list1″) 
Runestone.academy Also, it describes how we can take advantage of the ordered lists if our comparisons are smart. When we look at the first item in a sequential search, we have no more than (n-1) items to compare with if that is not the right item. Binary searches will not search the list in a sequential order. Instead, they will look at the middle one. Once we’re have finding the right item, then we can move on to the next. We can remove half the items from the list if it’s not the right item. We know the lower half as well as middle items can be removed from consideration if the item that we’re looking for exceeds the one we have. If the item is on the list, it must be found in the upper part. Last edited 43 days ago, by Jelani Paris (Xi An Shaanxi in China). 
According to analysts tutorialspoint.comThe basic concept behind binary search is to compare the needed element with each element in the array. We will instead compare the requested element with the middle of the array. We are finished if this is the element that we were looking for. If an element you are searching for is greater than the middle, it will ensure that it lies in the’s leaving-most or first part of the array. This is because the array is sorted. The same applies to the case where the element you are trying to find is larger than the middle one. It is certain that it lies in the first or left half of the array.